Mathematics

Maharashtra Board Ā· English Ā· Class 10 Ā· 2 questions with solutions

Q1NUMERICALMEDIUM

Find the 19th term of the following AP,

7,13,19,25......

Answer: 115

Solution:

The given sequence is 7, 13, 19, 25, ....

Here,

First term = a = t1 = 7, t2 = 13, t3 = 19, t4 = 25, ....

Common difference = d = t2 - t1

= 13 -7

= 6

To find the 19th term, we have to use the formula, i.e.,

tn = a + (n - 1)d

t19 = 7 + (19 - 1) Ɨ 6 ...(On substituting value)

=7+ 18 Ɨ 6

= 7 + 108

= 115

Therefore the 19th term of the progression is 115.

Q2MCQEASY

Choose the correct example of prime number?

A)

2

āœ”
B)

4

C)

6

D)

8

Solution:

A) 2

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