UP Board · English · Class 12 · 1 question with solutions
Calculate the amount of work done to dissociate a system of three point charges +2 μC, +3 μC, and −5 μC placed at the vertices of an equilateral triangle of side length 20 cm.
Given: q1 = +2 μC, q2 = +3 μC, q3 = −5 μC, r = 0.20 m. Potential Energy: U = (¼πε0 · 1/r) [q1q2 + q2q3 + q3q1] U = (9 × 109 / 0.20) × [ (2)(3) + (3)(−5) + (−5)(2) ] × 10−12 U = 4.5 × 1010 × [−19] × 10−12 = −0.855 J Work done to dissociate: Wdissociate = −U = +0.855 J
Want to build a full paper from questions like these?
Section-wise blueprints, internal choices and answer keys — generated inside the Tufee app.
Get the Tufee app →